SQL SERVER 递归查询
SQL SERVER 2005之前的版本只能用函数方法实现，SQL SERVER 2005之后新增了CTE功能，可以利用CTE实现递归查询；
CTE：公用表达式Common Table Expression 是SQL SERVER 2005版本之后引入的一个特性；
#填充测试数据
1、sql
Create table GroupInfo( int, nvarchar(50), int)
Insert GroupInfo
select 0,'某某大学',null union all
select 1,'外语学院',0 union all
select 2,'英语专业',1 union all
select 3,'日语专业',1 union all
select 4,'英语专业一班',2 union all
select 5,'英语专业二班',2 union all
select 6,'日语专业一班',3 union all
select 7,'日语专业二班',3 union all
select 8, '法学院',0 union all
select 9, '刑法学专业',8 union all
select 10,'经济法学专业',8 union all
select 11,'刑法学专业一班',9 union all
select 12,'刑法学专业二班',9 union all
select 13,'经济法学专业一班',10 union all
select 14,'经济法学专业二班',10
2、效果图
#递归实现Demo
1、根据指定的节点向上获取所有父节点,向下获取所有子节点
--根据指定的节点向下获取所有子节点
with
CTE
as
(
select * from GroupInfo where Id=1
union all
select G.* from CTE inner join GroupInfo as G
on CTE.Id=G.ParentGroupId
)
select * from CTE order by Id
--根据指定的节点向上获取所有父节点
with
CTE
as
(
select * from GroupInfo where Id=14
union all
select G.* from CTE inner join GroupInfo as G
on CTE.ParentGroupId=G.Id
)
select * from CTE order by Id
2、构造递归路径
--构造递归路径
with
CTE
as
(
select Id,GroupName,ParentGroupId,GroupPath=CAST( GroupName as nvarchar(max)) from GroupInfo where Id=1
union all
select G.*,CAST(CTE.GroupPath+'//'+G.GroupName as nvarchar(max)) as GroupPath from CTE
inner join GroupInfo as G
on CTE.Id=G.ParentGroupId
)
select * from CTE
3、分组递归，将同一条分支上节点放到一起
--通过id字段的字符串的拼接，形成sort字段，再通过sort排序，来实现同一分支上的节点放到一起
WITH
CTE
AS
(
SELECT * ,CAST(RIGHT('000' + CAST( AS VARCHAR), 3) AS VARCHAR(MAX)) AS sort FROM GroupInfo
WHERE ParentGroupId = 0
UNION ALL
SELECT GroupInfo.* ,CAST(sort + RIGHT('000' + CAST(GroupInfo. AS VARCHAR),3) AS VARCHAR(MAX)) AS sort
FROM CTE
INNER JOIN GroupInfo ON CTE.Id = GroupInfo.ParentGroupId
)
SELECT * FROM CTE ORDER BY sort
4、递归层级查询（查询出节点所属的层级）
--查询节点层级
WITH CTE AS (
SELECT *,1 AS FROM GroupInfo WHERE ParentGroupId=0
UNION ALL
SELECT G.*,CTE.Level+1 FROM GroupInfo as G
JOIN CTE ON CTE.Id =G.ParentGroupId
)
SELECT * FROM CTE
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